CATAGORY: Mechanics QUESTION: At room temperature, an oxygen molecule, with mass 5.31 x 10-26 kg, typically has a KE of about 6.21 x 10-21 J. How fast is it moving?

Back to uncited catalog.

Back to catalog.

We will make the simplifying assumption here that all of the KE is in translational kinetic energy and not rotational energy. This gives us (1) KE = 6.21 x 10-21 J or (2) 1 - m v^2 = 6.21 x 10-21 J 2 Where m is the mass of the molecule and v is its velocity. Solving for v (3) v = sqrt( 2 x 6.21 x 10-21 J / m ) = sqrt( 2 x 6.21 x 10-21 J / 5.31 x 10-26 kg ) = 484 m/s *************** * * * v = 484 m/s * * * ***************

Back to catalog.